/ [r!(n - r)!] Now, to determine the number of 6-card hands containing at least one copy of the card you desire, you use: nCr(copies of card, # in starting hand) x nCr((cards in deck - copies of card), (cards being drawn - # in starting hand)) nCr(copies of card, # in starting hand) x nCr(cards in deck - copies of card), (cards being drawn - # in starting hand)) nCr(3,1) x nCr(40-3,6-1) + nCr(3,2) x nCr(40-3,6-2) + nCr(3,3) x nCr(40-3,6-3) = 1,513,596 That determines the possibility of drawing one, two, or three copies of the card in your starting hand
Pokmon
You can't even play lands with this
bit.ly/4e6Demd More Pokmon cards were printed last year than there are humans on Earth, but new card releases are still plagued by scalping, in-store squabbles, and constant sell-outs